In the figure above, PQRS is a circle with ST//RQ. Find the value of x PT = PS.
- A.
70^{o} - B.
55^{o} - C.
40^{o} - D.
35^{o}
Correct Answer: Option B
Explanation
PQRS is a cyclic quad^{^}P = 180 – 110 (opp ∠s of a cyclic quad)^{^}P = 70
In ΔPTS, ^{^}S = ^{^}T (base ∠s of Isc Δ)
∴^{^}T = (180-70) / 2
= 110/2
= 55^{o}
But ^{^}T x(corr ∠)
∴x =55