The nth term of a sequence is represented by 3 x 2

^{(2-n)}. Write down the first three terms of the sequence-
**A.**^{3}/_{2}, 3, 6 -
**B.**

6, 3,^{3}/_{2} -
**C.**^{3}/_{2}, 3,^{1}/_{3} -
**D.**^{2}/_{3}, 3,^{8}/_{3} -
**E.**^{3}/_{2}, 0, 6

##### Correct Answer: Option B

##### Explanation

When n = 1, n = 2, n = 3

3 x 2^{2 – 1} = 6

3 x 2^{2 – 2} = 3

3 x 2^{2 – 3} = ^{3}/_{2}