Three straight lines EF, GH and LK interest at O as shown above. If ∠KOF = 52o and ∠LOH = 85o, calculate the size of ∠EOG.
Correct Answer: Option B
∠GOK = 85o (vertical opposite angle ∠s)
∠EOG + ∠GOK + ∠KOF = 180 (∠s on a straight line)
∠EOg + 85o + 52o = 180o
∠EOG + 137o = 180o
∠EOG = 43o