Evaluate (int_0^{frac{pi}{2}}sin2xdx)
- A.
1 - B.
zero - C.
-1/2 - D.
-1
Correct Answer: Option A
Explanation
(int_0^{frac{pi}{2}})sin 2x dx = [-1/2cos 2x + C](_0^{frac{pi}{2}})
=[-1/2 cos 2 * π/2 + C] – [-1/2 cos 2 * 0]
= [-1/2 cos π] – [-1/2 cos 0]
= [-1/2x – 1] – [-1/2 * 1]
= 1/2 -(-1/2) = 1/2 + 1/2 = 1