Mathematics

Evaluate (int_0^{frac{pi}{2}}sin2xdx)

Evaluate (int_0^{frac{pi}{2}}sin2xdx)

  • A.
    1
  • B.
    zero
  • C.
    -1/2
  • D.
    -1
Correct Answer: Option A
Explanation

(int_0^{frac{pi}{2}})sin 2x dx = [-1/2cos 2x + C](_0^{frac{pi}{2}})
=[-1/2 cos 2 * π/2 + C] – [-1/2 cos 2 * 0]
= [-1/2 cos π] – [-1/2 cos 0]
= [-1/2x – 1] – [-1/2 * 1]
= 1/2 -(-1/2) = 1/2 + 1/2 = 1