Find the gradient of a line which is perpendicular to the line with the equation 3x + 2y + 1 = 0
- A.^{3}/_{2}
- B.^{2}/_{3}
- C.
–^{2}/_{3} - D.
–^{3}/_{2}
Correct Answer: Option B
Explanation
3X + 2Y + 1 = 0
2Y = -3X – 1
(frac{-3}{2}X – frac{1}{2})
Gradient of 3X + 2Y +1 = 0 is –^{3}/_{2}
Gradient of a line perpendicular to 3X + 2Y + 1 = 0
(=-1 div frac{3}{2}\
=-1 times frac{-2}{3}=frac{2}{3})