Mathematics

Evaluate (int_1 ^2(6x^2-2x)dx)

Evaluate (int_1 ^2(6x^2-2x)dx)
  • A.
    16
  • B.
    13
  • C.
    12
  • D.
    11
Correct Answer: Option D
Explanation

(int_1 ^2(6x^2-2x)dx=[frac{6x^3}{3}-frac{2x^2}{2}]_1 ^2\
= [2x^3 – x^2]_1^2)
= [2(2)3 – (2)2] – [2(1)3 – (1)2]
= [16-4] – [2-1]
= 12 – 1
= 11