Mathematics

Evaluate (int^{frac{pi}{2}} _{frac{-pi}{2}} cos x dx)

Evaluate (int^{frac{pi}{2}} _{frac{-pi}{2}} cos x dx)
  • A.
    zero
  • B.
    1
  • C.
    2
  • D.
    3
Correct Answer: Option C
Explanation

(int^{frac{pi}{2}} _{frac{-pi}{2}} cos x dx = [sinx]^{frac{pi}{2}} _{frac{-pi}{2}}\
=sinfrac{pi}{2} – sinfrac{-pi}{2})
= sin90 – sin-90
= sin90 – sin270
= 1 – (-1)
= 1+1
= 2