Find the acute angle between the straight lines y = x and y = √3x
- A.
15^{o} - B.
30^{o} - C.
45^{o} - D.
60^{o}
Correct Answer: Option A
Explanation
y = x, Gradient (m_{1}) = 1
y = √3x gradient (m_{2}) = √3
(tantheta = frac{m_2 – m_1}{1+m_2 m_1}\
tantheta = frac{sqrt{3}-1}{1+sqrt{3}times 1}\
=frac{1.73 -1 }{1+1.73}=
frac{0.73}{2.73}=0.268)
θ = Tan^{-1} (0.268)
= 15^{o}