Mathematics

In the diagram above, O is the center of the circle, |SQ| = |QR| and…

In the diagram above, O is the center of the circle, |SQ| = |QR| and ∠PQR = 68°. Calculate ∠PRS

  • A.
    34o
  • B.
    45o
  • C.
    56o
  • D.
    62o
  • E.
    68o
Correct Answer: Option A
Explanation

From the figure, < PQR = 68°

(therefore) < QRS = < QSR = (frac{180 – 68}{2}) (base angles of an isos. triangle)

= 56°

(therefore) < PRS = 90° – 56° = 34° (angles in a semi-circle)