Mathematics

In the diagram above, O is the center of the circle QOR is a diameter…

In the diagram above, O is the center of the circle QOR is a diameter and ∠PSR is 37°. Find ∠PRQ

  • A.
    37o
  • B.
    53o
  • C.
    65o
  • D.
    127o
  • E.
    147o
Correct Answer: Option B
Explanation

Construction: Join PQ.

Then < RSP = 37° = < RQP (angles on the same segment)

But < RPQ = 90° (angle in a semi-circle)

(therefore) < PRQ = 180° – (90° + 37°)

 = 53°