Mathematics

simplify; 2log(_{3}) 6 + log(_{3}) 12 – log(_{3}) 16

simplify; 2log(_{3}) 6 + log(_{3}) 12 – log(_{3}) 16

  • A.
    2
  • B.
    3
  • C.
    2 – 2log32
  • D.
    3 – log32
  • E.
    4 – log32
Correct Answer: Option B
Explanation

2log(_{3}) 6 + log(_{3}) 12 – log(_{3}) 16

= (log_3 6^2 + log_3 12 – log_3 16)

= (log_{3} (frac{36 times 12}{16}))

= (log_{3} (27))

= (log_{3} 3^3)

= (3 log_{3} 3)

= 3