Mathematics

In the diagram above, ∠PRQ = 90°, ∠QPR = 30° and /PQ/ = 10 cm. Find…

In the diagram above, ∠PRQ = 90°, ∠QPR = 30° and /PQ/ = 10 cm. Find y.

  • A.
    6cm
  • B.
    5cm
  • C.
    4cm
  • D.
    3cm
  • E.
    2cm
Correct Answer: Option B
Explanation

(sin 30° = frac{y}{10})

(y = 10 sin 30° = 10 times 0.5 = 5 cm)